本文共 3017 字，大约阅读时间需要 10 分钟。
这里运算符的重载比较难
总时间限制:
1000ms
内存限制:
65536kB
// 在此处补充你的代码
描述
程序填空，输出指定结果
#include#include #include #include using namespace std;const int MAX = 110; class CHugeInt {
};int main() { char s[210]; int n; while (cin >> s >> n) { CHugeInt a(s); CHugeInt b(n); cout << a + b << endl; cout << n + a << endl; cout << a + n << endl; b += n; cout << ++ b << endl; cout << b++ << endl; cout << b << endl; } return 0;} 输入
多组数据，每组数据是两个非负整数s和 n。s最多可能200位， n用int能表示
输出
对每组数据，输出6行，内容分别是：
样例输入
99999999999999999999999999888888888888888812345678901234567789 126 6
样例输出
999999999999999999999999998888888888888888123456789012345678019999999999999999999999999988888888888888881234567890123456780199999999999999999999999999888888888888888812345678901234567801252526121212131314
来源
Guo Wei
#include#include #include #include using namespace std;const int MAX = 110; class CHugeInt { // 在此处补充你的代码private: char c[200];public: // 将字符串反转 void reverse(char *a) { int i = 0, j = strlen(a) - 1; while (i < j) { swap(a[i], a[j]); i++; j--; } } CHugeInt(const char* a) { int len; memset(c, 0, 200); // 把c全部置为0 strcpy(c, a); len = strlen(c); reverse(c); } CHugeInt(int n) { int len; memset(c, 0, 200); // 把c全部置为0 sprintf(c, "%d", n);//把n转换为char存在c len = strlen(c); reverse(c); } CHugeInt operator +(const CHugeInt &b)const { CHugeInt a(0); int lenb = strlen(b.c); int len = strlen(c); int lena; if (b.c[0] == '0' && lenb == 1) { // b为0的情况 return *this; } if (c[0] == '0' && len == 1) { // a为0的情况 strcpy(a.c, b.c); return a; } int j = 0; // 正常大数加法 for (int i = 0; i < len || i < lenb; i++) { int x = 0; char c1 = c[i], c2 = b.c[i]; if (c[i] == 0) c1 = '0'; // 注意前面处理中有的字符串位是用数字0填充的 if (b.c[i] == 0) c2 = '0'; x = c1 - '0' + c2 - '0' + j; // j是进位 a.c[i] = (x % 10) + '0'; // 处理进位 j = x / 10; // j是进位 } // 将字符串长度较大值，给新的字符串 lena = len > lenb ? len : lenb; // 如果还有进位 if (j != 0) { int a0 = len > lenb ? len : lenb; a.c[a0] = j + '0'; lena = a0 + 1; } return a; } CHugeInt operator +(int n) { return *this + CHugeInt(n); } friend CHugeInt operator +(int n, const CHugeInt &h) { // 这里用上面函数，传的引用 return h + n; } CHugeInt& operator +=(int n) { *this = *this + CHugeInt(n);//直接调用默认复制构造函数，因为char c[200]是数组不是指针 return *this; } friend CHugeInt& operator ++(CHugeInt &a) { a = a + 1; return a; } friend ostream& operator<<(ostream& o, const CHugeInt& a) { int len = strlen(a.c); for (int i = len-1; i >= 0; --i) { cout << a.c[i]; } return o; } friend CHugeInt operator ++(CHugeInt &a, int) { CHugeInt b = a; a = (b + 1); return b; }};int main() { char s[210]; int n; while (cin >> s >> n) { CHugeInt a(s); CHugeInt b(n); cout << a + b << endl; cout << n + a << endl; cout << a + n << endl; b += n; cout << ++ b << endl; cout << b++ << endl; cout << b << endl; } return 0;}
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